What is the line that passes through points 6,9 and 11,2

The final equation of line passing through (6,9) and (11,2)[tex]y=-\frac{7}{5}x+\frac{87}{5}[/tex]Further explanation:The general form of equation is:[tex]y=mx+b[/tex]We have to find the slope first[tex]m=\frac{y_2-y_1}{x_2-x_1}\\Here\\(x_1,y_1)=(6,9)\\(x_2,y_2)=(11,2)\\Putting\ the\ values\\m=\frac{2-9}{11-6}\\=-\frac{7}{5}[/tex]Putting the value of m in general form[tex]y=-\frac{7}{5}x+b[/tex]For finding the value of b, putting (6,9) in equation[tex]9=-\frac{7}{5}(6)+b\\9=-\frac{42}{5}+b\\9+\frac{42}{5}=b\\b=\frac{45+42}{5}\\[/tex][tex]b=\frac{87}{5}[/tex]Putting the values of b and mThe final equation of line passing through (6,9) and (11,2)[tex]y=-\frac{7}{5}x+\frac{87}{5}[/tex]Keywords: Equation of line, SlopeLearn more about equation of line at:brainly.com/question/10941043brainly.com/question/10978510#LearnwithBrainly